a pair of dice is thrown once find the probability of having a sum 11 on the two dice ?
Answers
Answered by
31
Sum is 11.
Lets count the favourable outcomes.
{( (5,6), (6,5)}
As we know there are a total of 36 possible outcomes i.e {(1,1),(1,2),…..,(6,5),(6,6)}
P(E) = Number of favourable outcomes / Total number of outcomes
= 2/36 = 1/18
Lets count the favourable outcomes.
{( (5,6), (6,5)}
As we know there are a total of 36 possible outcomes i.e {(1,1),(1,2),…..,(6,5),(6,6)}
P(E) = Number of favourable outcomes / Total number of outcomes
= 2/36 = 1/18
Answered by
11
Answer:
Step-by-step explanation:
Hlo guzz
Here, total outcome is 36
We all know (5,6) and (6,5) are the fv outcome
The favourable outcome=2
So
P(sum of getting 11 on both five)= favourable outcome / total out come
= 2/36 =1/18
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Hope you understand
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