A pair of dice is thrown once, find the probabity of getting doublet, if sum 6 has already appeared?
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Getting a doublet means getting same no. on both dice.
total outcomes when 2 dice are thrown are= 36
Total doublets=6 i.e (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
As the sum 6 has been appeared so we cancel the outcome (3,3)
Therefore we have now total 5 outcomes
⇒P(E) = 5\36
Please mark it as brainliest
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