a pair of dice is thrown the probability of getting sum of numbers more than 10
Answers
Answer:
ANSWER IS 1/12
Step-by-step explanation:
The probability of an event = number of outcomes in the event divided by number of outcomes in the sample space.
Since we are rolling 2 dice, the sample space (which contains every outcome that is possible) is:
S = {(1, 1) (1, 2), (1, 3),(1, 4 ),(1, 5),(1, 6 ),(2, 1 ),(2 , 2 ),(2, 3 ),(2, 4 ),(2, 5 ),(2, 6),
(3, 1 ),(3, 2 ),(3, 3 ),(3, 4 ),(3, 5 ),(3, 6),(4, 1 ),(4, 2 ),(4, 3),(4, 4 ),(4, 5 ),(4, 6 ),
(5, 1 ),(5, 2 ),(5, 3),(5, 4 ),(5, 5),(5, 6 ),(6, 1 ),(6, 2 ),(6, 3 ),(6, 4 ),(6, 5 ),(6, 6 )}
n(S) = 36
Our event is A=(the sum of the numbers obtained is more than 10)
A = { (5,6), (6,5), (6,6) }
n(A) = 3
Therefore, as stated above,
the probability of (A) = 3/36 = 1/12
Answer:
Total number of outcomes =36
Favorable outcomes for total of atleast 10 are
(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)
Number of favorable outcomes =6
Hence, the probability of getting a total of atleast 10 = 6/36 = 1/6