A pair of dice is thrown together till a sum of 4 or 8 is obtained. The probability that sum 4 appears before 8
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3/8 is the probability that sum 4 appears before 8
Step-by-step explanation:
A pair of dice is thrown together till a sum of 4 or 8 is obtained.
Two dice are thrown
total possible out comes = 36
Sum of 4 = (1 , 3) , (2 , 3) , ( 3 , 1)
Probability = 3/36
Sum of 8 = ( 2 , 6) , (3 , 5) , ( 4, 4) , ( 5, 3) , ( 6 , 2)
Probability = 5/36
Probability that Sum 4 appears before 8
= (3/36)/(3/36 + 5/36)
= 3/8
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