A pair of dice is tossed once, find the probability of getting
a) a total of 2
b) a total of 5
c) an even number as the sum
d) same number on each dice
Answers
To Find :
( a )The probability of getting a total of 5.
( b ) Even number as a sum .
( c ) Same number on each dice .
Solution :
When a pair of dice is thrown , the possible outcomes are :
There are a total of 36 possible outcomes.
( a ) The probability of getting a total of 5.
The outcomes should be ( 1, 4 ) , ( 2 , 3 ) , ( 3, 2 ) , ( 4 , 1 )
Therefore,
probability of getting a total of 5 = 4/36 = 1/9
( b ) Even number as sum .
Outcomes can either be both even or both odd.
Such outcomes are :
( 1, 1 ) , ( 1 , 3 ) , ( 2, 2 ) , ( 2, 4 ) etc .
It is half of the total outcomes.
probability of getting even number as sum = 18/36 = 1/2
( c ) Same number on each dice .
Outcomes are ( 1 , 1 ) ,( 2 , 2 ) , ( 3, 3 ) , ( 4, 4 ) , ( 5, 5) , ( 6 , 6 ).
Therefore there are 6 possible outcomes.
probability of getting same number on each dice = 6 / 36 = 1/6
Therefore the probability of getting a total of 5 = 1/9 ,
probability of getting even number as sum = 1/2 and
probability of getting same number on each dice = 1/6.
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