Question

A pair of die is thrown find the probability of getting a sum of 10 or more, if 5 appears an the first die

Answer 1

I hope 2/36 is answer

Answer 2

Answer:

$Probability = \frac{1}{18}$

Step-by-step explanation:

If two dice are rolled , out comes of the number on them can be expressed as follows:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4), (5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total number of out comes = n(S) = 6×6 = 36

Let the event that getting a sum of 10 or more , if 5 appears on the first die be ' E ' .

Possible outcomes to E = (5,5) and (5,6).

Number of possible outcomes to 'E' = n(E)=2

$Probability = P(E) = \frac{n(E)}{n(S)}\\=\frac{2}{36}\\=\frac{1}{18}$

Therefore,

$Probability = \frac{1}{18}$

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