Math, asked by bhattkarankumar, 7 months ago

A pair of die is thrown once find the probability of getting sum is greater than 10.​

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Answered by rajrsharma2007
0

Answer:

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Answered by HHM14
1

Answer:

THE REQUIRE POSSIBILITIES ARE:

5+5,6+6

6+4,6+5

4+6,5+6

TOTAL NUMBER OF POSSIBILITIES ARE:

5+5,6+6,4+4,3+3,2+2,1+1,

6+4,4+6,6+3,3+6,6+2,2+6,6+1,1+6,6+5,5+6,

5+4,4+5,5+3,3+5,5+2,2+5,1+5,5+1,

4+3,3+4,4+2,2+4,1+4,4+1

3+2,2+3,3+1,1+3,

2+1,1+2,

PROBABILITY=NO. OF FAVOURABLE OUTCOME/

TOTAL NO. OF OUTCOME

=6/29

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