Question

A pair of fair dice is thrown. Find the probability that the sum is ten or greater if

Answer 1

Answer:

1/6 or 0.167 or 16.7%

Step-by-step explanation:

We know that each dice has 6 faces, and the range of numbers for the faces are 1,2,3,4,5 &6

Since we are dealing with two faire dices, then the combination of faces for two dices are 6*6, which is 36 combinations.

Now, iterating through the combination,

dice1 dice2 sum

1        1           2

1 2 3

1 3 4

1 4 5

1 5 6

1 6 7

2 1 3

2 2 4

2 3 5

2 4 6

2 5 7

2 6 8

...etc

So, we don't see a sum that's equal to 10 or greater until dice1 = 4.  When

dice1=4 and dice=6, now that sum is 10.

Now the other combinations that meet this criteria are:

5, 5 => 10

5,6 => 11

6,4 => 10

6,5 => 11

6,6 => 12

So there are  6 events that would meet the criteria. Since the total is combination 36 and 6 events meet the criteria, we can write the probability as

6/36 => 1/6