A pair of linear equations which has a unique solution x = 2, y = –3 is a) x – 4y –14 = 0 5x – y – 13 = 0 b) 2x – y = 1 3x + 2y = 0 c) x + y = –1 2x – 3y = –5 d) 2x + 5y = –11 4x + 10y = –22
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If x = 2, y = – 3 is a unique solution of any pair of equation, then these values must satisfy that pair of equations.
From option (b), LHS = 2x + 5y = 2(2) + 5(- 3) = 4 – 15 = – 11 = RHS
and LHS = 4x + 10y = 4(2) + 10(- 3)= 8 – 30 = – 22 = RHS
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