Question

a pair of linear equations which has a unique solution x=2 y=-3 is
(a) x+y =-1 and 2x-3y=-5
(b) 2x+5y=-11 and 4x-10y=-22
(c) 2x-y=1 and 3x+2y=0
(d) x-4y-14=0 and 5x-y-13=0

Answer 1

Answer:

If x = 2, y = – 3 is a unique solution of any pair of equation, then these values must satisfy that pair of equations.

From option (b), LHS = 2x + 5y = 2(2) + 5(- 3) = 4 – 15 = – 11 = RHS

and LHS = 4x + 10y = 4(2) + 10(- 3)= 8 – 30 = – 22 = RHS

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