Math, asked by rchhalaria, 8 months ago

A pair of linear equations which has a unique
solutions x =
2, y=-3 is
(1) x + y = - 1, 2x – 3y = -5
(2) 2x + 5y = - 11, 4x + 10y = - 22
(3) 2x - y = 1, 3x + 2y = 0
(4) x - 4y - 14 = 0, 5x - y - 13 = 0​

Answers

Answered by kichu2609maq
5

Answer:(2) and (4)

Step-by-step explanation:

We know that x=2 and y=-3

Substituting the values in (2),

2(2)+5(-3)=10-15=-11

Similarly, 4(2)+10(-3)=8-30=-22

Hence the solution is x=2andy=-3 for the equation.

Hence one answer is (2).

Now, substituting the same in (4),

2-4(-3)-14=2+12-14=14-14=0

5(2)-(-3)-13=10+3-13=13-13=0

Hence the answer to this equation is also x=2,y=-3

Therefore (4) is also one answer.

Answered by Anonymous
2

Answer:

your answer is in the above attachment.

and thanks for thanking my answers.

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