A pair of negative integers whose difference is 8
Answers
Answered by
62
Step-by-step explanation:
(-1,-9) and (-3,-11) are two pairs whose difference is 8.
(-1,-9) and (-3,-11) are two pairs whose difference is 8.We can write infinitely many pairs .
Step-by-step explanation:
Negative Integers = { .......,-5,-4,-3,-2,-1}
Let -1, -9 are two negative integers.
i )Difference of two numbers = -1-(-9)
= -1 + 9
= 8
ii) Let -3, -11 are two negative integers.
Difference of these two numbers = -3-(-11)
= -3+11
= 8
Therefore,
(-1,-9) and (-3,-11) are two pairs whose difference is 8.
We can write infinitely many pairs .
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Answered by
21
Answer:
(-2) - (-10)
-2+10
8
Step-by-step explanation:
hope it is helpful
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