Question

a pair of opposite angle of parallelogram are 40x and 50y write a linear equation

Answer 1

We know that, opposite angles of a parallelogram are equal.
Therefore, 40x=50y
Transposing 50y to LHS,
40x-50y=0
Now, taking 10 common,
10(4x-5y)=0
Therefore 
4x-5y=0·10=0
Therefore, Linear Eq.-->  4x-5y+0=0

Answer 2

In a parallelogram, the opposite angles are equal.
Thus 40x = 50y
⇒ 40x - 50y = 0
⇒ 10(4x - 5y) = 0
⇒ 4x - 5y = 0

The required linear equation is 4x - 5y = 0.