Question

A pair of unbiased dice is thrown. Find the probability that (1) the sum
of spots is either 5 or 10, and (ii) either there is a doublet or a sum less
than 6.​

Answer 1

Answer:

(i) 7/36 (ii) 7/18

Step-by-step explanation:

(i) sum to be 5: 2+3,3+2, 1+4, 4+1

sum to be 10: 4+6, 6+4, 5+5

total possible outcomes when we throw two dice is 36

5 or 10= 4/36+ 3/36= 7/36

(ii) doublet : 1+1,2+2,3+3,4+4,5+5,6+6

sum less than 6: 1+1,1+2,2+1,2+2,1+3,3+1,2+3,3+2,4+1,1+4

doublet or sum <6= 14/36= 7/18 ( Since 1+1 and 2+2 are common)

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