Question

A paper in the form of a square ABCD in which AB= 14cm. A semicircular portion

with AD as diameter is cut off. Find the area of the remaining paper.​

Answer 1

Answer:

Since BC is the diameter, so radius = d/2 = 14/2 = 7 cm

Radius = 7 cm

Area of the semicircular portion = 1/2πr²

= 1/2*22/7*7*7

Area of the semicircular portion = 77 sq cm

Area of the rectangle ABCD = L*B

= 20*14

Area of the rectangle ABCD = 280 sq cm

Now area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion

= 280 - 77

= 203 sq cm