a paper inthe form of rectangular piece PQRS in which PQ=40Cm and QR=28cm. A semicircular portion with QR as diameter is cutoff. Find the area of the remaining part
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Area of the Paper = l x b
= 28 x 40
= 1120cm2
Area of cutoff = 2 pi r
= 2 x 22/7 x 14
= 88 cm2
The Remaining Area = Area of paper - Area of cutoff
= 1120 - 88
= 1032cm2
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