Question

a paper inthe form of rectangular piece PQRS in which PQ=40Cm and QR=28cm. A semicircular portion with QR as diameter is cutoff. Find the area of the remaining part​

Answer 1

Area of the Paper = l x b

                              = 28 x 40

                              = 1120cm2

Area of cutoff =  2 pi r

                       = 2 x 22/7 x 14

                       = 88 cm2

The Remaining Area = Area of paper - Area of cutoff

                                  = 1120 - 88

                                  = 1032cm2