Question

A paper is in form af square of side 14 cm.
Semicircles are drawn in side af square paper
on two sides as diameter . The semi-circular portions are cut off. Find area of remaining
pape (Take pi =22/7)
​

Answer 1

Answer:

Area of a square = 14cm× 14cm

= 196 cm2

let side of a square be the diameter of a semi circles is 14cm

radius of a semi circles = 7cm

Area of a semi circles = 1/2 × 22/7 × 49cm2

= 77cm2 + 77cm2

= 154cm2

Area of the remaining part = (196 - 154) cm2

= 42cm2

Answer 2

The area of remaining paper is  $42\ cm^{2}$.

Step-by-step explanation:

Given:

A paper is in form of square of side 14 cm.

Semicircles are drawn in side of square paper on two sides as diameter.

The semi-circular portions are cut off.

To Find:

The area of remaining paper.

Solution:

As given,A paper is in form of square of side 14 cm.

Length of  side of square form paper  =14 cm.

Area of square form paper $=(Length\ of\ side) ^{2}$

                                             $=14^{2} =196\ cm^{2}$

As given,semicircles are drawn in side of square paper on two sides as diameter.

Diameter of semicircles = Length of side of square paper

                                        = 14 cm.

Radius of a semi circles $=\frac{Diameter}{2} =\frac{14}{2} =7 cm.$

Area of a semi circle $= \frac{1}{2}\times \pi (Radius\ of\ a\ semi circle)^{2}$

                                   $= \frac{1}{2} \times\pi \times 7^{2}$                                    

                                    $=\frac{1}{2} \times\frac{22}{7} \times7^{2}$

                                    $=77\ cm^{2}$

Area of two semi circles  $=2\times77= 154 cm^{2}$

The Area of the remaining part =Area of square form paper-Area of two semi circles

                                                    $=196-154= 42\ cm^{2}$

Thus, the area of remaining paper is  $42\ cm^{2}$.

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