A paper is in form of rectangle having length 28cm and breadth 21cm . A semicircular portion with breadth as a diameter is cut off. The area of remaining portion is what?
Answers
Answered by
0
Answer: 280cm^2
Step-by-step explanation:
28*21-28/2*22/7
=560-616/2
=560-308
=280
Answered by
0
Answer:
Step-by-step explanation:
28×21-π(21/2)^2/2
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