a paper is in the form of a rectangle ABCD in which AB=20 cm, BC=14 cm. a semi-circular portion with BC as diameter is cut off . find the area of the remaining part.{Use π = 22/7} plss solve it fast
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Ans =203 cm ^2
Area of rectangle = 20 * 14= 280cm ^2
Area of semi circle = pie r^2 /2 = 22/7*7*7/2 11*7 = 77
Area of left over paper =280-77
203cm^2
Area of rectangle = 20 * 14= 280cm ^2
Area of semi circle = pie r^2 /2 = 22/7*7*7/2 11*7 = 77
Area of left over paper =280-77
203cm^2
IshaSinnu:
ur answer is wrong is wrong the correct answer is 203 cm^2
I dint divide by 2
mm yep
Answered by
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Hello,
we have that:
diameter=BC=14 cm
we calculate the radius:
r=d/2=BC/2=14/2=7 cm
we calculate the area of circle:
Ac=πr²=22/7×7²=22×7=154 cm²
we calculate the areaof semi-circle:
Asc=Ac/2=154/2=77 cm²
we calculate the area of sheet:
As=b×h=20×14=280cm²
we calculate the area of remaning sheet:
A=As-Asc=280-77=203 cm²
bye :-)
we have that:
diameter=BC=14 cm
we calculate the radius:
r=d/2=BC/2=14/2=7 cm
we calculate the area of circle:
Ac=πr²=22/7×7²=22×7=154 cm²
we calculate the areaof semi-circle:
Asc=Ac/2=154/2=77 cm²
we calculate the area of sheet:
As=b×h=20×14=280cm²
we calculate the area of remaning sheet:
A=As-Asc=280-77=203 cm²
bye :-)
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