Math, asked by sneha34445, 1 year ago

A paper is in the form of a rectangle ABCD, in which AB=20 cm and BC= 14 cm. A semicircular portion with BC as diameter is cut off. Find the area of the remaining part. ( Use π = 22/7 ).

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Answered by pavanmeena16200366

2

Answer:

area of paper= l* b

20 *14=280

area of semicircle 22/7 *7*7*1/2= 77

area of remaining part is 203

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