A paper is in the form of a rectangle ABCD in which AB=20cm and bc =14cm. A semi circular portion with BC as diameter is cut off. Find the area of the remaining part.
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353
Solution:-
Since BC is the diameter, so radius = d/2 = 14/2 = 7 cm
Radius = 7 cm
Area of the semicircular portion = 1/2πr²
= 1/2*22/7*7*7
Area of the semicircular portion = 77 sq cm
Area of the rectangle ABCD = L*B
= 20*14
Area of the rectangle ABCD = 280 sq cm
Now area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion
= 280 - 77
= 203 sq cm
Answer.
Since BC is the diameter, so radius = d/2 = 14/2 = 7 cm
Radius = 7 cm
Area of the semicircular portion = 1/2πr²
= 1/2*22/7*7*7
Area of the semicircular portion = 77 sq cm
Area of the rectangle ABCD = L*B
= 20*14
Area of the rectangle ABCD = 280 sq cm
Now area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion
= 280 - 77
= 203 sq cm
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79
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