Question

A paper is in the form of a rectangle ABCD in which AB = l and BC = b. A semicircular portion with BC as diameter is cut off. The area of the remaining paper is​

Answer 1

Answer:

175^2

Step-by-step explanation:

Area of rectangular ABCD=l×b

=AB×BC

=18×14=252 cm

2

Radius of semicircle (r)

=

2

1

BC=

2

1

×14=7cm

∴ Area of semicircle

=

2

1

πr

2

=

2

1

×

7

22

×(7)

2

=77cm^2

Area of the remaining portion =Area of rectangle−Area of of Semicircle

=252−77

=175cm ^2