A paper is in the form of a rectangle in which AB is 16cm and BC is 12cm. A semi circular portion with BC as diameter is cut-off.Find the remaining part?
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Area of paper =16*12=192 cm^2
Area of circular portion=1/2*22/7*12/2*12/2
=11/7*6*6
=56.57
Area left=192-56.57
=135.43=ANS
MARK IT AS BRAINLIEST
Area of circular portion=1/2*22/7*12/2*12/2
=11/7*6*6
=56.57
Area left=192-56.57
=135.43=ANS
MARK IT AS BRAINLIEST
dhruvanandsingh:
pls mark as BRAINLIEST
Wrong answer
Answered by
0
Answer:
Step-by-step explanation: Radius = 12/2 .....=6cm
Area of semicircle = 1/2 πr^2
= 1/2( 22/7 x 6 x 6 )
= 396/7 cm^2
Area of rectangle = l x b
= 16 x 12
= 192 cm^2
Area of remaining portion= 196-396/7
= 196x7/1x7 - 396/7
( taking LCM)
= 938/7 cm^2
= 134 cm^2
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