Question

A paper is in the form of a rectangle PQRS in which PQ = 20 cm and QR = 14 cm. A semicircle portion
with QR as diameter is cut off. Find the area of the remaining part. but please the answer should be (126cm^2) with full solution ​

Answer 1

Answer:

Given, Length (PQ)= 10cm

Given, Breadth (QR) = 7cm

Area of Rectangle PQRS will be = 10 * 7

= 70cm^2

Given that two semicircles of Diameter QR and PS are cut off, then

Area of remaining part will be Area of the rectangle - Area of the semicircle

Area of semicircle = pi * r * r/2

= (22/7 * 3.5 *3.5 )/2

= 38.5/2

= 19.25cm^2

Area of two semicircles = 19.25 + 19.25

= 38.50cm^2

Area of remaining portion = 70 - 38.50

= 31.50cm^2.

Hope this helps!