Question

A paper is in the form of a rectangle PQRS in which PQ = 30 cm and QR = 21
cm. Q semicircular portion with QR as diameter is cut-off. Find the area of the
remaining part.

Please in Figure
Step by Step answer​

Answer 1

Answer:

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Answer 2

Answer:

457cm.sq

Step-by-step explanation:

area of remaining figure= area of rectangle- area of semi circle

area of rectangle= 30*21=630cm.sq

area of semi circle= πr^2/2

r=d/2=21/2

area of semi circle = 22/7(21/2)^2/2= 3.14*110.25/2= 173.0925cm.sq(173.approx.)

area of remaining part= 630-173= 457cm.sq

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