a paper is in the form of a rectangle pqrs in which pq is equal to 10 centimetre and qr = 7cm Two semicircular portion with qr and ps as diameter are cut off find the area of the remaining part
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two side rq and ps form semi circle so two semicircle is equal one complete circle which diameter is 7cm
area of circle =22/7x(7/2)^2=77/2cm^2
now area of rectangle=10x7=70cm^2
now remaining area=70-77/2=63/2 cm^2
area of circle =22/7x(7/2)^2=77/2cm^2
now area of rectangle=10x7=70cm^2
now remaining area=70-77/2=63/2 cm^2
abhi178:
I hope you understand
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