Question

A paper is in the form of rectangle ABCD in which ab =22 cm and BC = 14 cm of a circle semicircle portion with BC as diameter is cut off find the area of remaining part

Answer 1

Hlw mate!!


Solution:-

Since BC is the diameter, so radius = d/2 = 14/2 = 7 cm
Radius = 7 cm
Area of the semicircular portion = 1/2πr²
= 1/2*22/7*7*7
Area of the semicircular portion = 77 sq cm
Area of the rectangle ABCD = L*B
= 20*14
Area of the rectangle ABCD = 280 sq cm
Now area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion
= 280 - 77 
= 203 sq cm
Answer.

Hope it helpful