Question

- A paper is in the form of rectangle having length 28
cm and breadth 21 cm. A semicircular portion with
breadth as a diameter is cut off. The area of
remaining portion is
(a) 400 cm2
(b) 404 cm
(C) 410.75 cm
(d) 414.75 cm2 with sollution ​

Answer 1

Ans414.75

cm sq.

Step-by-step explanation:

area of paper remaining= area of paper -area of semicircle.

area of remaining paper=(28×21) - (π×21/2×21/2)/2

= 588-{(22/7)×(441/8)

= 588-{(22×63)/8}

=588-173.25

=414.75 cm sq.

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