Question

A paper is in the form of rectangle pqrs in which PQ equal to 10 centimetre and QR is equal 7cm. 2 semicircular portions with QR and PS as diameters are cut off find the area of the remaining part

Answer 1

As from the figure I made, it is clear that the area of the quadrilateral PQRS is:-

Area of rectangle= Length* breadth

                           = 10 cm* 7 cm

                           = 70 sq. cm.

Area of circle 1 - as can be clearly seen from the figure, the diameter is 7cm. So, radius will be= 3.5 cm

 Area of circle 1= π * r^2

                         = 22/7 * 3.5 * 3.5

                         = 38.48 cm^2

now, area of 1/2 of both circles is equal. SO, 1/2 of circle 1= 1/2 of circle 2

1/2+1/2= 1

therefore,

the area of both circles will be equal to area of 1 circle= 38.48 cm^2

Now,

 area of remaining figure= Area of PQRS- Area of circles= (70- 38.48) cm^2

= 31.52 cm^2

Hope it helps! Smash that mark as brainliest and comment for any doubt!