a paper is in the former of a rectangle pqrs pq=10 cm and qr=7 cm . two semi circular portion with
Answers
Answer:
Given, Length (PQ)= 10cm
Given, Breadth (QR) = 7cm
Area of Rectangle PQRS will be = 10 * 7
= 70cm^2
Given that two semicircles of Diameter QR and PS are cut off, then
Area of remaining part will be Area of the rectangle - Area of the semicircle
Area of semicircle = pi * r * r/2
= (22/7 * 3.5 *3.5 )/2
= 38.5/2
= 19.25cm^2
Area of two semicircles = 19.25 + 19.25
= 38.50cm^2
Area of remaining portion = 70 - 38.50
= 31.50cm^2.
Hope this helps!
Step-by-step explanation: