Question

A parachutist after bailing out, falls 50 m without friction. When parachute opens, it deccelerates at 2 m/s2 • He reaches the ground with a speed of 3 m/s. At what height did he bail out?

Answer 1

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Answer 2

Answer:

293 m

Explanation:

Initial velocity, u=  root  2gh

that is  u=  2×9.8×50

=14  root 5

​The velocity at ground, v=3 m/s

$v^{2}-u^{2} = 2as$

that is 3^2 −980=2×(−2)×s

thus s=971/4

, which is nearly 243 m.

Initially he has fallen 50 m

Thus total height at which he bailed out=243+50=293 m