Question

. A parachutist drops freely from an aeroplane
for 8s before the parachute opens out. Then
he descends with a net retardation of 2 ms-2
reaching the ground with a velocity of 6 ms-1.
The height from which he bails out of the
aeroplane is (g = 10 ms-2)
1) 1929 m
2) 1911 m
3) 2195 m
4) 2000 m​

Answer 1

Answer:

Correct option is

C

1591 m

v=ut+at  

=0+10×8  

=80 m/s  

s=ut+  

2

1

​

at  

2

 

=0+  

2

1

​

×10×8  

2

 

=320 m  

v  

f

2

​

=v  

i

2

​

+2as  

s=  

2a

v  

f

2

​

−v  

i

2

​

 

​

 

=  

2×(−2)

6  

2

−80  

2

 

​

 

=1591 m

Explanation: