Physics, asked by sathyanarayana19, 11 months ago

A parachutist flying in an aeroplane iumps when it is at a height
aeroplane jumps when it is at a height of 3 km above ground.
He opens his parachute when he is about 1km above ground. Descriu

Answers

Answered by basavaraj5392
8

Answer:

Suppose the aeroplane is flying horizontally. Now parachutist is like a freely falling body in vertically downward direction and has uniform velocity equal to aeroplane velocity in horizontal direction till he opens parachute at a height 1km from the ground.

now after opening parachute , air resistance and buoyancy force also acts on him along with gravitational force. in the presence of these forces , net acceleration of parachutist becomes zero after falling through certain height . now he attains constant velocity known as terminal velocity and finally he reaches the ground with the same terminal.

Answered by bhavani2000life
0

Answer:

Consider that the Aeroplane is flying horizontally. The person jumping from the aeroplane is treated as a freely falling body because, his intial velocity in the vertically downward direction is Zero (0).

-> Sometime after opening the parachute the person get a Uniform Velocity called "Terminal Velocity" due to air friction. Hence, the Acceleration becomes Zero. Thus, the person falls with a constant velocity.

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