a parallel beam of light is made to fall on a concave mirror .an image is formed at a dis. of 7.5 cm from the mirror.what are the focal length and the radius of curvature of the mirror.
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Answered by
89
1/v + 1/u = 1/f
so v = distance of object form mirror = infinity(i)
u = distance of image from mirror = 7.5
f = focal length of mirror = f
1/i + 1/7.5 = 1/f
0 + 1/7.5 = 1/f
f = 7.5 cm ANSWER
so v = distance of object form mirror = infinity(i)
u = distance of image from mirror = 7.5
f = focal length of mirror = f
1/i + 1/7.5 = 1/f
0 + 1/7.5 = 1/f
f = 7.5 cm ANSWER
Answered by
40
u the dist of the object is assumed to be zero. v the dist of the image=7.5cm f the focal length=? theradius of curvature=2f=? using the equn 1/u +1/v=1/f 0+1/7.5=1/f or f the focal length=7.5cm rthe radius of curvature=2f =2 x7.5 15cm
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