a parallel beam of light of wavelength 5890 Armstrong is incident on a glass plate having refractive index 1.5 such that the angle of refraction in the plate is 60 degree. calculate the smallest thickness of glass plane which will appear dark by reflected light.
pls solve this sum using the formula
2utcosr=n×lamda
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Answer:
Explanation:
Let the thickness of the Glass slab is t
The condition for minimum thickness corresponding to a dark band is 2μtcosr=λ
∴t=
2μcosr
λ
=
2×1.5×cos60
o
5890×10
−10
t=3926×10
−10
m=3926
A
o
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