Physics, asked by 20100219110018, 4 months ago

‘A parallel combination of resistors is better than series combination of resistors’. Justify the statement with an example.​

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Answered by devilsahil2005
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Answer:

Resistors in Series and Parallel

Learning Objectives

By the end of the section, you will be able to:

Define the term equivalent resistance

Calculate the equivalent resistance of resistors connected in series

Calculate the equivalent resistance of resistors connected in parallel

In Current and Resistance, we described the term ‘resistance’ and explained the basic design of a resistor. Basically, a resistor limits the flow of charge in a circuit and is an ohmic device where V=IR. Most circuits have more than one resistor. If several resistors are connected together and connected to a battery, the current supplied by the battery depends on the equivalent resistance of the circuit.

The equivalent resistance of a combination of resistors depends on both their individual values and how they are connected. The simplest combinations of resistors are series and parallel connections ((Figure)). In a series circuit, the output current of the first resistor flows into the input of the second resistor; therefore, the current is the same in each resistor. In a parallel circuit, all of the resistor leads on one side of the resistors are connected together and all the leads on the other side are connected together. In the case of a parallel configuration, each resistor has the same potential drop across it, and the currents through each resistor may be different, depending on the resistor. The sum of the individual currents equals the current that flows into the parallel connections.

(a) For a series connection of resistors, the current is the same in each resistor. (b) For a parallel connection of resistors, the voltage is the same across each resistor.

Par a shows four resistors connected in series and part b shows four resistors connected in parallel.

Resistors in Series

Resistors are said to be in series whenever the current flows through the resistors sequentially. Consider (Figure), which shows three resistors in series with an applied voltage equal to {V}_{ab}. Since there is only one path for the charges to flow through, the current is the same through each resistor. The equivalent resistance of a set of resistors in a series connection is equal to the algebraic sum of the individual resistances.

(a) Three resistors connected in series to a voltage source. (b) The original circuit is reduced to an equivalent resistance and a voltage source.

Part a shows original circuit with three resistors connected in series to a voltage source and part b shows the equivalent circuit with one equivalent resistor connected to the voltage source.

In (Figure), the current coming from the voltage source flows through each resistor, so the current through each resistor is the same. The current through the circuit depends on the voltage supplied by the voltage source and the resistance of the resistors. For each resistor, a potential drop occurs that is equal to the loss of electric potential energy as a current travels through each resistor. According to Ohm’s law, the potential drop V across a resistor when a current flows through it is calculated using the equation V=IR, where I is the current in amps (A) and R is the resistance in ohms \left(\text{Ω}\right). Since energy is conserved, and the voltage is equal to the potential energy per charge, the sum of the voltage applied to the circuit by the source and the potential drops across the individual resistors around a loop should be equal to zero:

\sum _{i=1}^{N}{V}_{i}=0.

This equation is often referred to as Kirchhoff’s loop law, which we will look at in more detail later in this chapter. For (Figure), the sum of the potential drop of each resistor and the voltage supplied by the voltage source should equal zero:

\begin{array}{ccc}\hfill V-{V}_{1}-{V}_{2}-{V}_{3}& =\hfill & 0,\hfill \\ \hfill V& =\hfill & {V}_{1}+{V}_{2}+{V}_{3},\hfill \\ & =\hfill & I{R}_{1}+I{R}_{2}+I{R}_{3},\hfill \\ \hfill I& =\hfill & \frac{V}{{R}_{1}+{R}_{2}+{R}_{3}}=\frac{V}{{R}_{\text{eq}}}.\hfill \end{array}

Since the current through each component is the same, the equality can be simplified to an equivalent resistance, which is just the sum of the resistances of the individual resistors.

Any number of resistors can be connected in series. If N resistors are connected in series, the equivalent resistance is

{R}_{\text{eq}}={R}_{1}+{R}_{2}+{R}_{3}+\text{⋯}+{R}_{N-1}+{R}_{N}=\sum _{i=1}^{N}{R}_{i}.

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