Question

A parallel plate air capacitor has a capacitance
C. When it is half filled with a dielectric of
dielectric constant 5, the percentage increase in
the capacitance will be
(a) 400% (b) 66.6%
(c) 33.3% (d) 200%

Answer 1

Explanation:

C(air)=k×C(dielectric)

where k is dielectric constant

suppose initial Capacitance is C

the after inserting dielectric it becomes 5C

so percentage change is =C(final)-C(initial)÷initial×100

=(5C-C÷C)×100

=4×100

=400%