a parallel plate air capacitor is charged to a potential difference of v volts . After disconnecting from battery, the plates of capacitor is pushed gently by an insulating handle to decrease the seperation between them . as a result the charge on plate
1) decreases
2)increases
3) becomes zero
4) remains same
Answers
Answered by
7
Answer:
increases
Explanation:
thanks my answer please
Answered by
0
Answer:
In ∆ABC, ∠B=90°
, ∠C=
° and cot= √3 , then sin(90-) is
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