A parallel plate capacitor(C1) having charge Q is connected ,to a uncharged capacitor (C2) in parallel.What would be the charge accumulated on the capacitor C2 ?
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ctotal=c1+c2
ctotal=q1/v1+q2c2
ctotal=q1/v1+q2c2
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When a charged and an uncharged capacitor is connected in series, the charges re-distribute themselves in the direct connection to their capacitance, holding the whole charge of the circuit fixed.
So, charge across C2 is Q/2.
Mathematically,
Let the charge, capacitance and voltage of the two capacitors be, Q1, C1, V1 and Q2, C2, V2 respectively.
Because they are attached in series,
V=V1+V2 = Q1/C1 = Q2/C2
We know, C1 = C2 = C
Hence, V= (Q1+ Q2)/C
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