Question

A parallel plate capacitor consists of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of 5 1013 v/s, then the value of displacement current is:

Answer 1

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Answer 2

Given :

Radius of plate , r = 2 cm .

Distance between the plates , $d = 0.1\ mm = 10^{-4}\ m$ .

Variation of voltage , $\dfrac{dE}{dt}=5\times 10^{13}\ V/s$ .

To Find :

The value of displacement current .

Solution :

Area if circular plate is given by :

$A=\pi r^2=\pi\times 0.02^2\\\\A=1.25\times 10^{-3}\ m^2$

We know , displacement current is given by :

$I_d=\epsilon_oA\dfrac{dE}{dt}$

Putting all values in above equation :

We get :

$I_d=8.85\times 10^{-12}\times 1.25\times 10^{-3}\times 5\times 10^{13}\\\\I_d=0.55\ A$

Therefore , the value of displacement current is 0.55 A .

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Capacitors

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