Question

A parallel plate capacitor, each with plate area A & separation d, is charged to a p.d V.

The battery used to charge it remains connected. A dielectric slab of thickness d & dielec-

tric constant K is now placed between the plates. What change if any, will take place in

(a) charge on the plates?

(b) electric field between the plates?

(c) capacitance of the capacitor?​

Answer 1

Explanation:

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