A parallel plate capacitor has a plate separation 0.01 and use a direct electric 19 the maximum potential difference'
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Explanation:
Suppose there is a parallel-plate capacitor but the two plates have different areas, A1 and A2. How will we derive an expression for its capacitance?
I have been told to take the area common between the two, but from where does this follow?
Ideally we start off by assuming that one plate has +Q charge and the other has −Q. Then we find that the potential difference V is directly proportional to Q, from which we find capacitace C.
I am unable to find the potential difference.
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