Question

A parallel plate capacitor has circular plates of 10 cm radius separated by an air gap of 1 mm. It is charged by connecting the plates to a 100 volt battery. Find the change in energy stored in the capacitor when the plates are moved to a distance of 1 cm and the plates are maintained in connection with the battery...only a valid answer on notebook ​

Answer 1

Answer:

1J =10^7erg so 125.05×10^-8J is equal to 12.5 erg.. so this is the loss of energy because U2 is less than U1. This discussion on A parallel plate capacitor has circular plates of 10 cm radius separated by an air-gap of 1 mm. It is charged by connecting the plates to a 100 volt battery.

Explanation:

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