Question

A parallel plate capacitor has plate area of 10 cm^3and a separation of 0.885mm bw the plate find the capacitance

Answer 1

Given ,

• Area of each plates (A) = 10 cm² or (10)^-1 m²

• Distance b/w two plates (d) = 0.885 mm or 8.85 × (10)^-4 m

We know that ,

The capacitance of parallel plates is given by

$\large \mathtt{\fbox{C = \frac{ e_{o}A }{d}} }$

Thus ,

$\sf \hookrightarrow C = \frac{ \cancel{8.85 } \times {(10)}^{ - 12} \times {(10)}^{ - 1} }{ \cancel{8.85} \times {(10)}^{ - 4} } \\ \\ \sf \hookrightarrow C = 1 \times {(10)}^{ (- 13 + 4)} \\ \\\sf \hookrightarrow C = 1 \times {(10)}^{ - 9} \: \: farad$Hence , the capacitance of parallel plate capacitor is 1 × (10)^-9