Question

A parallel plate capacitor has square plate size of 50m and separated by a distance of 1mm .find the capacitance of the capacitor?

Answer 1

Answer:

General Expression of Capacitance in a parallel plate capacitor is :

C = \dfrac{A \epsilon_{0} }{d}C=

d

Aϵ

0

\implies C = \dfrac{ {(side)}^{2} \epsilon_{0} }{d}⟹C=

d

(side)

2

ϵ

0

Putting necessary values in SI UNITS:

\implies C = \dfrac{ {(50)}^{2} \epsilon_{0} }{ \frac{1}{1000} }⟹C=

1000

1

(50)

2

ϵ

0

\implies C = 25 \times {10}^{5} \times \epsilon_{0}⟹C=25×10

5

×ϵ

0

\implies C = 25 \times {10}^{5} \times 8.85 \times {10}^{ - 12}⟹C=25×10

5

×8.85×10

−12

\implies C = 221.25 \times {10}^{ - 7}⟹C=221.25×10

−7

\implies C = 22.125 \times {10}^{ - 6} \: F⟹C=22.125×10

−6

F

\implies C = 22.125 \: \mu F⟹C=22.125μF

So, capacitance is 22.125 micro-F.