Question

A parallel plate capacitor has square plates of size 50 m and separated bya distance of 1mm. Find the capacitance of the capacitor.​

Answer 1

General Expression of Capacitance in a parallel plate capacitor is :

$C = \dfrac{A \epsilon_{0} }{d}$

$\implies C = \dfrac{ {(side)}^{2} \epsilon_{0} }{d}$

• Putting necessary values in SI UNITS:

$\implies C = \dfrac{ {(50)}^{2} \epsilon_{0} }{ \frac{1}{1000} }$

$\implies C = 25 \times {10}^{5} \times \epsilon_{0}$

$\implies C = 25 \times {10}^{5} \times 8.85 \times {10}^{ - 12}$

$\implies C = 221.25 \times {10}^{ - 7}$

$\implies C = 22.125 \times {10}^{ - 6} \: F$

$\implies C = 22.125 \: \mu F$

So, capacitance is 22.125 micro-F.