Question

A parallel plate capacitor has two plates of dimensions 10 cm x 7 cm separated by distance of 0.7 mm. A glass plate of thickness 0.4 mm​

Answer 1

Answer:

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Explanation:

I am use Trignometry method and binomial method

Answer 2

The capacitance is $1.69\times 10^{-10}\ F$ .

Given :

Dimensions of parallel plate capacitor is 10 cm x 7 cm .

Distance between the plates , d = 0.7 mm = 0.0007 m .

Thickness of glass plate t = 0.4 mm​ = 0.0004 m .

Dielectric constant of glass , k = 6 .

We know , capacitance is given by :

$C=\dfrac{\epsilon_oA}{d-t(1-\dfrac{1}{k})}$

Putting all values in above equation we get :

$C=\dfrac{8.85\times 10^{-12}\times 0.007}{(7-4(1-\dfrac{1}{6}))\times 10^{-4}}\\\\C=1.69\times 10^{-10}\ F$

Hence , this is the required solution .

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Capacitor

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