Question

A parallel plate capacitor having a plate separation of 2 mm is charged by connecting it to a 300 v supply. the energy density is

Answer 1

checkvand solution and your answer

Answer 2

Answer:

0.1 J/m

Explanation:

The energy per unit volume or the energy density is given by  

U=1/2ε0E^2...(i)  

where ε0 is permittivity of free space and E is electric field.  

Also,E=V/d...(ii)    

From Eqs. (i) and (ii), we have  

U=1/2ε0(V/d)^2  

Given V = 300 volt, d = 2 mm = 2×10^-3 m,  

ε0=8.85×10^-12 C^2/N/m^2

∴U=1/2×8.85×10^-12×(300/2×10^-3)^2

U=0.1 J/m