A parallel plate capacitor having plates of area S and plate separation d, has capacitance C₁ in air. When
two dielectrics of different relative permittivities (????₁ = 2 and ????₂ = 4) are introduced between the two plates
as shown in the figure, the capacitance becomes C₂. The ratio C₂/C₁ is
(A) 6/5 (B) 5/3
(C) 7/5 (D) 7/3
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Answer:
Capacitance
d
ϵ
0
A
C
3
and C
4
are in series.
C
1
=
d
ϵ
0
S
,C
3
=
2
d
ϵ
1
2
S
, C
4
=
2
d
ϵ
2
2
S
,C
5
=
d
ϵ
1
2
S
,C
34
=
C
3
+C
4
C
3
C
4
C
2
=C
34
+C
5
=
3
7
d
ϵ
0
S
C
1
C
2
=
3
7
solution
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