Question

A parallel plate capacitor is charged and then isolated. Now a dielectric slab is introduced in it. Which of the following quantities will remain constant ?(A) Electric charge Q (B) Potential difference V(C) Capacitance C (D) Energy U.

Answer 1

Here, the capacitor is disconnected. It is as of now charged or else there would be no power.

Be that as it may, when the dielectric is embedded, the charge stays settled.

In case the capacitor was associated with a voltage source, at that point current would stream to keep the voltage settled and afterward the power would increment.

The voltage goes down despite the fact that there is no present in or out.

Answer 2

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☸ Required Answer is ⬇ ⬇⬇ ⬇⬇ ⬇


⭕ A). Electric charge


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